## Equations to learn:

Equations for constant acceleration

v = u + at

s = 1/2 (u + v) t

s = ut + 1/2at^2

s = vt - 1/2at^2

v^2 = u^2 + 2as

When solving kinematic quesitons:

A cat is walking at

s = 1/2 (u + v) t

5 =4.5t

**s = displacement (m)****u = initial velocity (m/s)****v = final velocity (m/s)****a = acceleration (m/s^2)****t = time (s)**v = u + at

**(no s)**s = 1/2 (u + v) t

**(no a)**s = ut + 1/2at^2

**(no v)**s = vt - 1/2at^2

**(no u)**v^2 = u^2 + 2as

**(no t)**When solving kinematic quesitons:

- Write down
**S U V A T**in a vertical line **Fill**in values from the question- Generally you are given 3 values and asked to work out a 4th, so find what the question doesn't need initially( could be a two parter) and
**find the equation**without it - Fill in the numbers and
**solve**for the unit you want

**Example**A cat is walking at

**9 m/s**and comes to a**stop**after**5 metres**. Deceleration was constant. Find out how long it took the cat to come to rest.**S = 5m****U = 9 m/s****V = 0 m/s****A = n/a****T = ?**s = 1/2 (u + v) t

**5**= 1/2 (**9**+**0**) t5 =4.5t

**t = 10/9 s**The Quadratic Equation

The quadratic equation is used for solving quadratic equations in the form :

a^2 + a + 0

Each part corresponds to a letter which is used in inputting the numbers into the formula.

So for example:

2x^2 + 4x + 3 = 0

Then after inputting the numbers you will receive two numbers (one using minus, one using plus) and these will be your answers

The quadratic equation is used for solving quadratic equations in the form :

a^2 + a + 0

Each part corresponds to a letter which is used in inputting the numbers into the formula.

So for example:

2x^2 + 4x + 3 = 0

**a b c**Then after inputting the numbers you will receive two numbers (one using minus, one using plus) and these will be your answers